Identify each species in the following equilibrium according to the code: $SA = \text{stronger acid}$; $SB = \text{stronger base}$; $WA = \text{weaker acid}$; $WB = \text{weaker base}$. The $pK_a$ of $(CH_3)_2NH_2^+$ is $10.7$ (conjugate acid of $(CH_3)_2NH$) and the $pK_a$ of $CH_3OH$ is $15.2$.
$CH_3OH$ $(1)$ + $(CH_3)_2NH$ $(2)$ $\rightleftarrows CH_3O^- + (CH_3)_2NH_2^+$

• A
  $1 = WA, 2 = WB$
• B
  $1 = WB, 2 = WA$
• C
  $1 = SA, 2 = SB$
• D
  $1 = SB, 2 = SA$